Thanks Derlyn I can know rest. Sent from my CPH2197 using Tapatalk
You need not use 50% of full load. Any percentage will work as the volt drop will be directly proportional to the load drawn. Remember this
OK, Got It, This is very Informative Information, Thanks.
Good day As per the below reg what calculation is the calculation for full load conditions. I know we used 50 percent of circuit
Yes, just wanted to give some info as this is what the thread was about.
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Calculate for full load conditions
Thanks Derlyn
Gtfast Yesterday, 06:26 PMI can know rest.
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