Thank you so much for the reply and advice, i appreciate it. the battle on this side is also how some inspectors read SANS10142 -1. Sorry
Thanks Derlyn I can know rest. Sent from my CPH2197 using Tapatalk
You need not use 50% of full load. Any percentage will work as the volt drop will be directly proportional to the load drawn. Remember this
OK, Got It, This is very Informative Information, Thanks.
Good day As per the below reg what calculation is the calculation for full load conditions. I know we used 50 percent of circuit
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Hi Derlyn
Thank you so much for the reply and advice, i appreciate it.
Dennis28 Today, 07:08 AMthe battle on this side is also how some inspectors read SANS10142 -1.
Sorry